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Proof step 14 from proof bitsor-ones-false (previous step)

∀ bits1, bits0. # bits0 < # bits → true → bits0 = [] ∨ bitsor(bits0, false ' + bits1) = bits0 ∨ false ∈ bits0 ⊦ # bits = 1, bits = false ', bits = [], bitsor(bits, false ') = bits, false ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ bits ≠ [] ∧ bits0 = false ' → bitsor(bits, bits0) = bits

Rule argument

name: or-rec-02 rotate: F subst: [bits0, bits] → [false ', bits]

Additional information

Used terms: false ', bits