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Proof step 17 from proof bitsor-ones-false (previous step)

∀ bits1, bits0. # bits0 < 1 → true → bits0 = [] ∨ bitsor(bits0, false ' + bits1) = bits0 ∨ false ∈ bits0 ⊦ bitsor(true ', false ' + bits1) = true '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ bits0 ≠ [] ∧ bits = true ' → bitsor(bits, bits0) = true '

Rule argument

name: or-rec-03 rotate: F subst: [bits0, bits] → [false ' + bits1, true ']

Additional information

Used simplifier rules: ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ boolvar ' ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: false ' + bits1, true '