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Proof step 4 from proof bitsor-ones-false (previous step)

⊦ bits = [], bitsor(bits, false ' + bits1) = bits, false ∈ bits

User applied rule induction

And obtained the following new goals

Proof step 5:
true, ∀ bits1, bits0. # bits0 < # bits → true → bits0 = [] ∨ bitsor(bits0, false ' + bits1) = bits0 ∨ false ∈ bits0 ⊦ bits = [] ∨ bitsor(bits, false ' + bits1) = bits ∨ false ∈ bits

Rule argument

indvar: # bits wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # bits