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Proof step 1 from proof bitsor-ones-samelen (conclusion)

⊦ ¬ false ∈ bits ∧ # bits = # bits0 ∧ bits ≠ [] ∧ bits0 ≠ [] → bitsor(bits, bits0) = bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# bits = # bits0 ⊦ bits = [], bits0 = [], bitsor(bits, bits0) = bits, false ∈ bits

Rule argument

Additional information