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Proof step 17 from proof bitsor-sgn-in (previous step)

¬(¬ false ∈ bits ∧ ¬ bits0.first ∧ bits ≠ [] ∧ bits0 ≠ []), true ∈ bits ⊦ bits0 = [], bits = [], boolvar ↔ boolvar ∈ bitsor(bits, bits0), false ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
true ∈ bits, bits0.first ⊦ bits0 = [], bits = [], boolvar ↔ boolvar ∈ bitsor(bits, bits0), false ∈ bits

Proof step 17 from proof bitsor-sgn-in (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information