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Proof step 20 from proof bitsor-sgn-in (previous step)

true ∈ bits ⊦ bits = [], boolvar ↔ boolvar ∈ bitsor(bits, true ' + bits1), false ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ ¬ false ∈ bits ∧ bits0.first ∧ # bits ≤ # bits0 ∧ bits ≠ [] ∧ bits0 ≠ [] → bitsor(bits, bits0) = bits
Proof step 22:
¬(¬ false ∈ bits ∧ (true ' + bits1).first ∧ # bits ≤ #(true ' + bits1) ∧ bits ≠ [] ∧ true ' + bits1 ≠ []), true ∈ bits ⊦ bits = [], boolvar ↔ boolvar ∈ bitsor(bits, true ' + bits1), false ∈ bits

Rule argument

name: bitsor-ones-true rotate: F subst: [bits0, bits] → [true ' + bits1, bits]

Additional information

Used terms: true ' + bits1, bits