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Proof step 34 from proof bitsor-sgn-in (previous step)

# bits0 = # bits1, true ∈ bits2 ⊦ # bits2 = 1, bits1 = [], bits0 = [], bits2 = [], bits2 + bits0 = [], boolvar ↔ boolvar ∈ bitsor(bits2, true ') ∨ boolvar ∈ bits0, false ∈ bits2, false ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 35:
⊦ bits ≠ [] ∧ bits0 = true ' → bitsor(bits, bits0) = true '

Rule argument

name: or-rec-01 rotate: F subst: [bits0, bits] → [true ', bits2]

Additional information

Used simplifier rules: ⊦ boolvar ∈ boolvar0 ' ↔ boolvar ↔ boolvar0; Used terms: true ', bits2