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Proof step 40 from proof bitsor-sgn-in (previous step)

⊦ bits = [], boolvar ∈ bits0 ↔ boolvar ∈ bitsor(bits, bits0), bits0 = [], true ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 41:
⊦ ¬ true ∈ bits ∧ bits0.first ∧ bits ≠ [] ∧ bits0 ≠ [] → bitsor(bits, bits0) = bits0
Proof step 42:
¬(¬ true ∈ bits ∧ bits0.first ∧ bits ≠ [] ∧ bits0 ≠ []) ⊦ bits = [], boolvar ∈ bits0 ↔ boolvar ∈ bitsor(bits, bits0), bits0 = [], true ∈ bits

Rule argument

name: bitsor-zeroes-true rotate: F subst: [bits0, bits] → [bits0, bits]

Additional information

Used terms: bits0, bits