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Proof step 52 from proof bitsor-sgn-in (previous step)

⊦ # bits0 = # bits2 ∧ bits ≠ [] ∧ bits0 ≠ [] ∧ bits1 ≠ [] ∧ bits2 ≠ [] → bitsor(bits + bits0, bits1 + bits2) = bitsor(bits, bits1) + bitsor(bits0, bits2)

Lemma bitsor-app