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Proof step 59 from proof bitsor-sgn-in (previous step)

# bits0 = # bits1 ⊦ # bits2 = 1, bits1 = [], bits0 = [], bits2 = [], bits2 + bits0 = [], ¬ boolvar ∨ true ∈ bits1 ↔ boolvar ∈ bitsor(bits2, false ') ∨ boolvar ∈ bits1, true ∈ bits2, true ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 60:
⊦ bits ≠ [] ∧ bits0 = false ' → bitsor(bits, bits0) = bits

Rule argument

name: or-rec-02 rotate: F subst: [bits0, bits] → [false ', bits2]

Additional information

Used simplifier rules: ⊦ ¬ true ∈ bits ∧ bits ≠ [] → (¬ false ∈ bits ↔ false); Used terms: false ', bits2