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Proof step 1 from proof bitsxor-zeros-01 (conclusion)

⊦ n ≤ # bits ∧ bits ≠ [] ∧ n ≠ 0 → bitsxor(bits, mklist(false, n)) = bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n ≤ # bits ⊦ bits = [], n = 0, bitsxor(bits, mklist(false, n)) = bits

Rule argument

Additional information