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Proof step 3 from proof bor-256-plus (previous step)

⊦ j0 < 2 ^ 8 ∧ 0 ≤ j0 ∧ 0 ≤ j → bor(j * 2 ^ 8, j0) = j * 2 ^ 8 + j0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ j0 < 2 ^ i ∧ 0 ≤ i ∧ 0 ≤ j0 ∧ 0 ≤ j → bor(j * 2 ^ i, j0) = j * 2 ^ i + j0

Rule argument

name: bor-2pot-plus rotate: F subst: [j0, i, j] → [j0, 8, j]

Additional information

Used simplifier rules: bor-def: ⊦ bor(i, j) = bits2int(bitsor(int2bits(i), int2bits(j)));% ⊦ i * j = j * i;% ⊦ i + j = j + i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: j0, 8, j