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Proof step 1 from proof bor-65536-plus (conclusion)

⊦ j0 < 65536 ∧ 0 ≤ j0 → bor(j * 65536, j0) = j * 65536 + j0

User applied rule cut formula

And obtained the following new goals

Proof step 2:
65536 = 2 ^ 16 ⊦ j0 < 65536 ∧ 0 ≤ j0 → bor(j * 65536, j0) = j * 65536 + j0

Rule argument

fma: 65536 = 2 ^ 16

Additional information

Used formulas: 65536 = 2 ^ 16