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Proof step 5 from proof bor-65536-plus (previous step)

¬(j0 < 2 ^ 16 ∧ 0 ≤ 16 ∧ 0 ≤ j0 ∧ 0 ≤ j) ⊦ j0 < 2 ^ 16 ∧ 0 ≤ j0 → bor(j * 2 ^ 16, j0) = j * 2 ^ 16 + j0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ j0 < 2 ^ i ∧ 0 ≤ i ∧ 0 ≤ j0 ∧ j < 0 → bor(j * 2 ^ i, j0) = j * 2 ^ i + j0

Rule argument

name: bor-2pot-plus-01 rotate: F subst: [j0, i, j] → [j0, 16, j]

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i * j = j * i;%j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used terms: j0, 16, j