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Proof step 3 from proof bor-com (previous step)

⊦ bcompl(band(bcompl(i), bcompl(j))) = bor(j, i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ bor(i, j) = bcompl(band(bcompl(i), bcompl(j)))

Rule argument

name: bor-notAndNot rotate: F subst: [j, i] → [i, j]

Additional information

Used simplifier rules: band-commutativity: ⊦ band(i, j) = band(j, i); Used terms: i, j