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Proof step 10 from proof bor-notAndNot (previous step)

bitsand(sgn(bitsinvert(int2bits(j))), sgn(bitsinvert(int2bits(i)))) ≠ [] ⊦ bits2int(bitsinvert(bitsand(bitsinvert(int2bits(i)), bitsinvert(int2bits(j))))) = bits2int(bitsinvert(sgn(bitsand(sgn(bitsinvert(int2bits(j))), sgn(bitsinvert(int2bits(i)))))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information