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Proof step 16 from proof bor-notAndNot (previous step)

bitsinvert(int2bits(j)) ≠ [] ∧ sgn(bitsinvert(int2bits(i))) ≠ [] ⊦ bitsand(sgn(bitsinvert(int2bits(j))), sgn(bitsinvert(int2bits(i)))) = [], bits2int(bitsinvert(bitsand(bitsinvert(int2bits(i)), bitsinvert(int2bits(j))))) = bits2int(bitsinvert(sgn(bitsand(sgn(bitsinvert(int2bits(i))), bitsinvert(int2bits(j))))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ bitsinvert(bits) = [] ↔ bits = [];% ⊦ sgn(bits) = [] ↔ bits = [];