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Proof step 4 from proof bor-notAndNot (previous step)

int2bits(i) ≠ [] ∧ int2bits(j) ≠ [] ⊦ bits2int(bitsinvert(bitsand(bitsinvert(int2bits(i)), bitsinvert(int2bits(j))))) = bits2int(bitsinvert(int2bits(bits2int(bitsand(sgn(bitsinvert(int2bits(j))), sgn(bitsinvert(int2bits(i))))))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ bits2int(bitsinvert(bitsand(bitsinvert(int2bits(i)), bitsinvert(int2bits(j))))) = bits2int(bitsinvert(int2bits(bits2int(bitsand(sgn(bitsinvert(int2bits(j))), sgn(bitsinvert(int2bits(i))))))))

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];