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Proof step 7 from proof bor-notAndNot (previous step)

¬ bitsand(sgn(bitsinvert(int2bits(j))), sgn(bitsinvert(int2bits(i)))) ≠ [] ⊦ bits2int(bitsinvert(bitsand(bitsinvert(int2bits(i)), bitsinvert(int2bits(j))))) = bits2int(bitsinvert(int2bits(bits2int(bitsand(sgn(bitsinvert(int2bits(j))), sgn(bitsinvert(int2bits(i))))))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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