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Proof step 1 from proof bxor-def-logic (conclusion)

⊦ bxor(i, j) = bor(band(i, bcompl(j)), band(bcompl(i), j))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ bxor(i, j) = bits2int(bitsxor(int2bits(i), int2bits(j)))
Proof step 3:
⊦ bits2int(bitsxor(int2bits(i), int2bits(j))) = bor(band(i, bcompl(j)), band(bcompl(i), j))

Rule argument

name: bxor-def rotate: F subst: [j, i] → [j, i]

Additional information

Used terms: j, i