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Proof step 17 from proof bxor-def-logic (previous step)

¬ bitsand(int2bits(i), sgn(bitsinvert(int2bits(j)))) ≠ [] ⊦ bits2int(bitsxor(int2bits(i), int2bits(j))) = bits2int (bitsor (int2bits(bits2int(bitsand(int2bits(i), sgn(bitsinvert(int2bits(j)))))), int2bits(bits2int(bitsand(sgn(bitsinvert(int2bits(i))), int2bits(j))))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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