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Proof step 26 from proof bxor-def-logic (previous step)

bitsand(sgn(bitsinvert(int2bits(i))), int2bits(j)) ≠ [] ⊦ bitsand(int2bits(i), sgn(bitsinvert(int2bits(j)))) = [], bits2int(bitsxor(int2bits(i), int2bits(j))) = bits2int(bitsor(sgn(bitsand(int2bits(i), sgn(bitsinvert(int2bits(j))))), sgn(bitsand(sgn(bitsinvert(int2bits(i))), int2bits(j)))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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