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Proof step 29 from proof bxor-def-logic (previous step)

bitsinvert(int2bits(i)) ≠ [] ∧ int2bits(j) ≠ [] ⊦ bitsand(sgn(bitsinvert(int2bits(i))), int2bits(j)) = [], bits2int(bitsxor(int2bits(i), int2bits(j))) = bits2int(bitsor(sgn(bitsand(int2bits(i), sgn(bitsinvert(int2bits(j))))), sgn(bitsand(bitsinvert(int2bits(i)), int2bits(j))))), bitsand(int2bits(i), sgn(bitsinvert(int2bits(j)))) = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ bitsinvert(bits) = [] ↔ bits = [];% ⊦ int2bits(j) ≠ [];