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Proof step 39 from proof bxor-def-logic (previous step)

⊦ bitsand(sgn(bitsinvert(int2bits(i))), int2bits(j)) = [], bits2int(bitsxor(int2bits(i), int2bits(j))) = bits2int(bitsor(sgn(bitsand(bitsinvert(int2bits(j)), int2bits(i))), sgn(bitsand(bitsinvert(int2bits(i)), int2bits(j))))), bitsand(bitsinvert(int2bits(j)), int2bits(i)) ≠ [] ∧ bitsand(bitsinvert(int2bits(i)), int2bits(j)) ≠ []

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 3

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