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Proof step 35 from proof bxor-flip-one-bit (previous step)

0 ≤ i, 2 ^ j * 2 < i, i < 2 ^ (j - 1), 2 ^ (j - 2) ≤ i, 0 < j ⊦ j = 0, j = 1, bitsxor(int2bits(i), false ' + true ' + mklist(false, i→n(j))) = [], bitsxor(int2bits(i), false ' + true ' + mklist(false, i→n(j))).first ∧ sgn(bitsxor(int2bits(i), false ' + true ' + mklist(false, i→n(j))))[0, false] = int2bits(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ 0 ≤ i → j ^ (i + 1) = j ^ i * j subst: [i, j] → [j, 2] rotate: T spec: int-pot inst: name: succ

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i; Used terms: j, 2