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Proof step 53 from proof bxor-flip-one-bit (
previous step
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⊦ 1 < # bits ∧ 1 < # bits0 → bitsxor(bits, bits0) = bitsxor(bits.butlast, bits0.butlast) + (¬(bits.last ↔ bits0.last))
Lemma
bitsxor-rec-01