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Proof step 3 from proof cast-add-2pot-01 (previous step)

⊦ 0 < i → cast(i, ~1 * 2 ^ i + ~ j) = cast(i, ~ j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 0 < i → cast(i, j * 2 ^ i + j0) = cast(i, j0)

Rule argument

name: cast-mult-add rotate: F subst: [j0, j, i] → [~ j, ~1, i]

Additional information

Used terms: ~ j, ~1, i