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Proof step 26 from proof cast-law-add-pos (previous step)

j1 + j0 = i1 + 2 ^ i, 0 ≤ i, 0 ≤ i0, 0 ≤ j1, j1 < 2 ^ i, 2 ^ (i - 1) ≤ j1, 0 < i, 0 ≤ j0, 0 ≤ i1 + 2 ^ i ⊦ cast(i, i1 + 2 ^ i) = cast(i, i1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 27:
⊦ 0 < i → cast(i, j + 2 ^ i) = cast(i, j)

Rule argument

name: cast-add-2pot rotate: F subst: [j, i] → [i1, i]

Additional information

Used terms: i1, i