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Proof step 5 from proof cast-law-and-one (previous step)

0 < i ⊦ bits2int(lastn(i→n(i), fillsgn(i→n(i), int2bits(bits2int(bitsand(int2bits(j), int2bits(j0))))))) = cast(i, band(cast(i, j), j0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: and-notempty-09: ⊦ bitsand(int2bits(i), int2bits(i0)) ≠ [];% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)%bits ≠ [] ⊦ int2bits(bits2int(bits)) = sgn(bits);