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Proof step 1 from proof cast-law-comm (conclusion)

0 < i, 0 < i0 ⊦ cast(i, cast(i0, j)) = cast(i0, cast(i, j))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
0 < i, 0 < i0, i < i0 ⊦ cast(i, cast(i0, j)) = cast(i0, cast(i, j))
Proof step 3:
¬(0 < i ∧ 0 < i0 ∧ i < i0), 0 < i, 0 < i0 ⊦ cast(i, cast(i0, j)) = cast(i0, cast(i, j))

Rule argument

name: cast-help-comm rotate: F subst: [j, i0, i] → [j, i0, i]

Additional information

Used terms: j, i0, i