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Proof step 8 from proof cast-law-compl (previous step)

0 < i ⊦ cast(i, ~ j - 1) = cast(i, ~(cast(i, j) + 1))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
0 < i ⊦ cast(i, j - j0) = cast(i, cast(i, j) - j0)
Proof step 10:
0 < i, 0 < i ⊦ cast(i, cast(i, ~ j) - 1) = cast(i, ~(cast(i, j) + 1))

Rule argument

name: cast-law-sub-one rotate: F subst: [j0, j, i] → [1, ~ j, i]

Additional information

Used terms: 1, ~ j, i