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Proof step 24 from proof cast-law-mult-pos (previous step)

j % 2 ^ i = 0, 0 ≤ j, 0 < i ⊦ cast(i, j * j0) = cast(i, cast(i, j) * j0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 25:
j ≠ 0 ⊦ i % j = 0 ↔ (∃ j0. i = j0 * j)

Rule argument

seq: j ≠ 0 ⊦ i % j = 0 ↔ (∃ j0. i = j0 * j) subst: [j, i] → [2 ^ i, j] rotate: F spec: int-div inst: name: modex

Additional information

Used simplifier rules: cast-mult-2pot: ⊦ 0 < i → cast(i, j * 2 ^ i) = 0;%cast-zero: ⊦ 0 < i → cast(i, 0) = 0;% ⊦ 0 < j → (i ^ j = 0 ↔ i = 0);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i;% ⊦ i * 0 = 0; Used terms: 2 ^ i, j