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Proof step 8 from proof cast-law-or-one (previous step)

0 < i ⊦ cast(i, bcompl(cast(i, band(bcompl(j), bcompl(j0))))) = cast(i, bcompl(band(bcompl(cast(i, j)), bcompl(j0))))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
0 < i ⊦ cast(i, band(j, j0)) = cast(i, band(cast(i, j), j0))
Proof step 10:
0 < i, 0 < i ⊦ cast(i, bcompl(cast(i, band(cast(i, bcompl(j)), bcompl(j0))))) = cast(i, bcompl(band(bcompl(cast(i, j)), bcompl(j0))))

Rule argument

name: cast-law-and-one rotate: F subst: [j0, j, i] → [bcompl(j0), bcompl(j), i]

Additional information

Used terms: bcompl(j0), bcompl(j), i