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Proof step 3 from proof cast-law-sub-one (previous step)

0 < i ⊦ cast(i, j + ~ j0) = cast(i, cast(i, j) - j0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
0 < i ⊦ cast(i, j + j0) = cast(i, cast(i, j) + j0)

Rule argument

name: cast-law-add-one rotate: F subst: [j0, j, i] → [~ j0, j, i]

Additional information

Used simplifier rules: ⊦ i + ~ j = i - j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: ~ j0, j, i