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Proof step 3 from proof cast-law-sub (
previous step
)
0 < i, 0 < i ⊦ cast(i, cast(i, j) - j0) = cast(i, cast(i, j) - cast(i, j0))
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 4
:
0 < i ⊦ cast(i, j - j0) = cast(i, j - cast(i, j0))
Rule argument
name: cast-law-sub-one-01 rotate: F subst: [j0, j, i] → [j0, cast(i, j), i]
Additional information
Used terms: j0, cast(i, j), i