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Proof step 20 from proof cast-law-xor-one (previous step)

0 < i, 0 < i, 0 < i, 0 < i, 0 < i ⊦ cast(i, bor(cast(i, band(bcompl(j), j0)), cast(i, band(cast(i, j), bcompl(j0))))) = cast(i, bor(cast(i, band(bcompl(cast(i, j)), j0)), cast(i, band(cast(i, j), bcompl(j0)))))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
0 < i ⊦ cast(i, band(j, j0)) = cast(i, band(cast(i, j), j0))
Proof step 22:
0 < i, 0 < i, 0 < i, 0 < i, 0 < i, 0 < i ⊦ cast(i, bor(cast(i, band(cast(i, bcompl(j)), j0)), cast(i, band(cast(i, j), bcompl(j0))))) = cast(i, bor(cast(i, band(bcompl(cast(i, j)), j0)), cast(i, band(cast(i, j), bcompl(j0)))))

Rule argument

name: cast-law-and-one rotate: F subst: [j0, j, i] → [j0, bcompl(j), i]

Additional information

Used terms: j0, bcompl(j), i