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Proof step 1 from proof cast-min (conclusion)

⊦ 0 < i → ~(2 ^ (i - 1)) ≤ cast(i, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i, 2 ^ (i - 1) + cast(i, j) < 0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ~ i ≤ j ↔ 0 ≤ i + j;