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Proof step 4 from proof cast-min (previous step)

¬(cast(i, j) < ~1 ∧ 0 ≤ i - 1), 0 < i, 2 ^ (i - 1) + cast(i, j) < 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < i, 2 ^ (i - 1) + cast(i, j) < 0, ~1 ≤ cast(i, j) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ 1 ≤ i ↔ 0 < i;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ ¬ i < j ↔ j ≤ i;