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Proof step 7 from proof cast-min (previous step)

cast(i, j) < ~1 ∧ 0 ≤ i - 1, 0 < i, ¬ # int2bits(cast(i, j)) ≤ i→n(i - 1) + 1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
cast(i, j) < 0, i→n(i - 1) + 1 < # int2bits(cast(i, j)), cast(i, j) < ~1, 0 < i ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ 1 ≤ i ↔ 0 < i;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;