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Proof step 2 from proof cast-mod-in (previous step)

j < 2 ^ (i - 1), 0 < i, 0 ≤ 2 ^ (i - 1) + j ⊦ cast(i, j) = j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
0 < i, abs(j) < 2 ^ (i - 1) ⊦ cast(i, j) = j
Proof step 4:
¬(0 < i ∧ abs(j) < 2 ^ (i - 1)), j < 2 ^ (i - 1), 0 < i, 0 ≤ 2 ^ (i - 1) + j ⊦ cast(i, j) = j

Rule argument

name: cast-mod-ls rotate: F subst: [j, i] → [j, i]

Additional information

Used terms: j, i