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Proof step 5 from proof cast-mod-in (previous step)

0 = 2 ^ (i - 1) + j, j < 0, j < 2 ^ (i - 1), 0 < i ⊦ cast(i, j) = j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
0 < i, j = ~(2 ^ (i - 1)) ⊦ cast(i, j) = j

Rule argument

name: cast-mod-ls-most rotate: F subst: [j, i] → [j, i]

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ~ i = j ↔ i + j = 0; Used terms: j, i