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Proof step 1 from proof cast-mod-ls-most (conclusion)

0 < i, j = ~(2 ^ (i - 1)) ⊦ cast(i, j) = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i ⊦ 2 ^ (i - 1) + cast(i, ~(2 ^ (i - 1))) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ ~ i = j ↔ i + j = 0;