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Proof step 16 from proof cast-mod-ls-most (previous step)

i→n(i) = #(true ' + mklist(false, i→n(i) - 1)), i→n(i) ≤ 1 + (i→n(i) - 1), 1 < i, 0 < i ⊦ 2 ^ (i - 1) + bits2int(true ' + mklist(false, i→n(i) - 1)) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
i→n(i) ≤ 1 + (i→n(i) - 1), 1 < i, 0 < i ⊦ 2 ^ (i - 1) + bits2int(true ' + mklist(false, i→n(i) - 1)) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ (m + n0) + n1 = m + n0 + n1;%n ≤ m ⊦ (m - n) + n0 = n1 ↔ m + n0 = n + n1;% ⊦ i < j → ¬ j < i;% ⊦ ¬ i ≤ j ↔ j < i;%0 ≤ i ⊦ (* m) ≤ i→n(i) ↔ n→i(m) ≤ i;% ⊦ 1 ≤ i ↔ 0 < i;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # mklist(boolvar, n) = n;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ m + n = n + m;