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Proof step 1 from proof cast-mod-ls-neg (conclusion)

0 < i, j < 0, abs(j) < 2 ^ (i - 1) ⊦ cast(i, j) = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i, j < 0, 0 < 2 ^ (i - 1) + j ⊦ cast(i, j) = j

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ ~ i < j ↔ 0 < j + i;% ⊦ i < 0 → abs(i) = ~ i;