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Proof step 1 from proof cast-mod-ls (conclusion)

0 < i, abs(j) < 2 ^ (i - 1) ⊦ cast(i, j) = j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
0 < i, 0 ≤ j, j < 2 ^ (i - 1) ⊦ cast(i, j) = j
Proof step 3:
¬(0 < i ∧ 0 ≤ j ∧ j < 2 ^ (i - 1)), 0 < i, abs(j) < 2 ^ (i - 1) ⊦ cast(i, j) = j

Rule argument

name: cast-mod-ls-pos rotate: F subst: [j, i] → [j, i]

Additional information

Used terms: j, i