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Proof step 14 from proof cast-mult-add-h (previous step)

0 = ~1 * 2 ^ i + 2 ^ i, 0 < i, ~1 * 2 ^ i < 0 ⊦ 0 = i, cast(i, ~1 * 2 ^ i) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ 0 < i → cast(i, j * 2 ^ i) = 0

Rule argument

name: cast-mult-2pot rotate: F subst: [j, i] → [~1, i]

Additional information

Used terms: ~1, i