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Proof step 26 from proof cast-mult-add-h (previous step)

0 < i, 0 = ~1 * 2 ^ i + 2 ^ i, 0 < i, j < 0, j < ~1, ~1 * 2 ^ i < 0 ⊦ 0 = i, 0 = cast(i, 0)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: cast-zero: ⊦ 0 < i → cast(i, 0) = 0;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ ~ i + i = 0;% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * ~1 = ~ i;