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Proof step 18 from proof cast-mult-add (previous step)

0 < i, 0 ≤ j0 % 2 ^ i ⊦ 0 < 2 ^ i ∧ 0 ≤ j0, cast(i, j * 2 ^ i + j0) = cast(i, j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
j0 % 2 ^ i = 0, 0 < i, j0 < 0 ⊦ cast(i, j * 2 ^ i + j0) = cast(i, j0)

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ j < 0 ∧ 0 < i → (0 ≤ j % 2 ^ i ↔ j % 2 ^ i = 0);% ⊦ i < j → ¬ j < i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ 0 < 2 ^ i ↔ 0 ≤ i;