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Proof step 1 from proof cast-mult-neg-01 (conclusion)

⊦ 0 < i → cast(i, ~(j * 2 ^ i)) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i ⊦ cast(i, ~(j * 2 ^ i)) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)