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Proof step 3 from proof cast-mult-neg-02 (
previous step
)
~(j * 2 ^ i + j0) = ~ j * 2 ^ i + ~ j0, 0 < i ⊦ cast(i, ~(j * 2 ^ i + j0)) = cast(i, ~ j0)
User applied rule insert equation
And obtained the following new goals
Proof step 4
:
0 < i ⊦ cast(i, ~ j * 2 ^ i + ~ j0) = cast(i, ~ j0)
Rule argument
pos: left 1 flags: discard
Additional information